Question

A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide.If $\Delta H$ is the enthalpy change and $\Delta E$ is the change in internal energy, then,

• A. $\Delta H > \Delta E$
• B. $\Delta H < \Delta E$
• C. $\Delta H = \Delta E$
• D. the relationship depends on the capacity of the vessel

Answer 1

Answer: (B)

$\Delta H < \Delta E$

Answer 2

$2 CO + O _{2} \longrightarrow 2 CO _{2}$ $\Delta H=\Delta E+\Delta n R T$ $\Delta \,n=$ No. of moles of gaseous product - No. of moles of gaseous reactant $\therefore\, \Delta n=2-3=-1$ $\Delta\, H=\Delta \,E-R T$ $\therefore, \Delta H