Solveeit Logo

Question

Physics Question on Thermodynamics

A mixture of one mole of a monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature (27C27^\circ \text{C}). The ratio of specific heat of gases at constant volume respectively is:

A

75\frac{7}{5}

B

32\frac{3}{2}

C

35\frac{3}{5}

D

53\frac{5}{3}

Answer

35\frac{3}{5}

Explanation

Solution

The specific heat capacities at constant volume are:
(CV)mono=32R,(CV)dia=52R.(C_V)_{\text{mono}} = \frac{3}{2}R, \quad (C_V)_{\text{dia}} = \frac{5}{2}R.
The ratio is:
(CV)mono(CV)dia=32R52R=35.\frac{(C_V)_{\text{mono}}}{(C_V)_{\text{dia}}} = \frac{\frac{3}{2}R}{\frac{5}{2}R} = \frac{3}{5}.
Final Answer: 3:53 : 5.