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Question: A mixture of \(MgO\) and \(Mg\) weighing \(10g\) is treated with excess of dilute \(HCl\) . Then \(2...

A mixture of MgOMgO and MgMg weighing 10g10g is treated with excess of dilute HClHCl . Then 2.24litre2.24litre of H2{H_2} gas was liberated under STP conditions. The mass of MgOMgO present in the sample is:
A. 2.4g2.4g
B. 7.6g7.6g
C. 8g8g
D. 2g2g

Explanation

Solution

STP refers to the standard condition for temperature and pressure. It is defined at the temperature of 273.15K273.15K and pressure of exactly 1atm1atm . At these two conditions of temperature and pressure the volume of one mole of substance is always 22.4litre22.4litre . Atomic mass of magnesium is 2424 .

Complete step by step answer:
According to the question, the reaction will be followed as:
Mg+2HClMgCl2+H2Mg + 2HCl \to MgC{l_2} + {H_2}
As we know that at STP one mole of magnesium will give 22.4litre22.4litre of H2{H_2} gas.
But according to the question,
The weight of magnesium used is giving 2.24litre2.24litre of H2{H_2} gas at STP will be calculated as:
 (2.24×2422.4)g 2.4g  \ \Rightarrow \left( {\dfrac{{2.24 \times 24}}{{22.4}}} \right)g \\\ \Rightarrow 2.4g \\\ \
Now, the total weight of magnesium oxide and magnesium is 10g10g
Mass of magnesium = 2.4g2.4g
So, weight of magnesium oxide will be :
 (102.4)g 7.6g  \ \Rightarrow (10 - 2.4)g \\\ \Rightarrow 7.6g \\\ \
The mass of MgOMgO is 7.6g7.6g .

Hence, option B is correct.

Note:
STP, which is standard temperature and pressure condition, is a reference which is used for the molar volume of an ideal gas. Hydrogen and helium are two gases which show positive deviation from ideal behavior at all pressure and 273K273K temperature. As are the lightest gases known. So, Their molecules have very small masses. So, the attractive forces between the molecules of these two gases are extensively small. So a/V2a/{V^2} is negligible even at ordinary temperatures. Thus PV>RTPV > RT . Thus the Vander Waals equation describes the observed behaviour of real gases (quantitatively) and so it is an improvement over the ideal gas equation. At all temperatures, if the pressure is extremely high then there will be a positive deviation because of the size of the molecules.The causes of deviations from ideal behaviour is due to the kinetic theory of gases. Kinetic theory of gas assumes that the volume occupied by gas molecules is very small as compared to the volume occupied by the gas and the forces of attraction between gas molecules are negligible.