A mixture of methylamine and dimethylamine is given to you.... | Chemistry | SolveeIt

Question

A mixture of methylamine and dimethylamine is given to you. The reagents used to separate the components of the mixture are

$\ce{CHCl_3 }$ and $\ce{ HCl}$

$\ce{C6H5SO_2Cl }$ and $\ce{KOH}$

$\ce{C6H5SO_2Cl }$ and $\ce{ HCl}$

$\ce{CHCl_3 }$ and $\ce{KOH}$

Answer

$\ce{C6H5SO_2Cl }$ and $\ce{KOH}$

Explanation

Solution

A mixture of methylamine (1? amine) and dimethylamine (2? amine) can be separated with the help of ${C_6H_5SO_2Cl}$ and KOH (Hinsberg's method).
Methylamine will form N-methylbenzenesulphonamide which is soluble in KOH. Dimethylamine will form N,N dimcthylbenzene sulphonamide which is insoluble in KOH.

Chemistry Question on Amines

Solution