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Question

Physics Question on Gas laws

A mixture of hydrogen and oxygen has volume 2000 cm3cm^3, temperature 300 K, pressure 100 kPa and mass 0.76 g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:[Take gas constant R = 8.3 JK1JK^{–1} mol1mol^{–1}]

A

13\frac{1}{3}

B

31\frac{3}{1}

C

116\frac{1}{16}

D

161\frac{16}{1}

Answer

31\frac{3}{1}

Explanation

Solution

P1V=n1RTP_1V = n_1RT

P2V=n2RTP_2V = n_2RT

(100kPa)V=(n1+n2)RT⇒ (100 kPa) V = (n_1 + n_2)RT

n1+n2=(100kPa)(2000cm)3)8.3×300.(1)⇒n_1+n_2=\frac{(100 kPa)(2000 cm)^3)}{8.3×300}….(1)

Also, n1×2+n2×32=0.76.(2)n_1 × 2 + n_2 × 32 = 0.76 ….(2)

Solving (1) and (2),

n1=0.06n_1 = 0.06

n2=0.02n_2 = 0.02

n1n2=3⇒ \frac{n_1}{n_2} = 3

Hence, the correct option is (B): 31\frac{3}{1}