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Question: A mixture of \(HCl\) and \({H_3}P{O_4}\) is titrated with \(1.0M\,NaOH\) .The first end point (Methy...

A mixture of HClHCl and H3PO4{H_3}P{O_4} is titrated with 1.0MNaOH1.0M\,NaOH .The first end point (Methyl red) occurs at 35.0mL35.0mL and second endpoints (Bromothymolblue) occurs at 50.0mL50.0\,mL .(15.0mL15.0mL after the first end point). The number of millimoles of HClHClpresent in the solution is___?

Explanation

Solution

Acid‐base titration is one of the most common operations in analytical chemistry. A solution containing an unknown amount of ionizable hydrogen can be titrated with a solution of standard base until all the hydrogen ions have been consumed .

Complete answer: Titration of HCl&H3PO4HCl\,\& \,{H_3}P{O_4} Mixture Using Indicators and a pH Meter.
The amount of NaOHNaOH used by phosphoric acid. = 15mL15mL
Therefore amount of phosphoric acid present is 15mL×1M15mL \times 1M=15millimoles15\,{\text{millimoles}}
[molarity=1M\because molarity = 1M]
During the first end point, out of 35mL35mL , 15mL15mL are used for neutralization of phosphoric acid.
\therefore The amount of NaOHNaOH used for neutralization of HCLHCL ,
HCl = 20 mL HCl=20mL×1M HCl = 20 millimoles  {\text{HCl = 20 mL}} \\\ {\Rightarrow {HCl = 20mL \times 1M}} \\\ {\Rightarrow \text{HCl = 20 millimoles}} \\\

Hence the number of millimoles of HClHCl present in the solution is 20millimoles.

Additional Information: Double titration:
The method involves two indicator phenolphthalein and methyl orange. This is a titration of specific compounds. Let us consider a solid mixture of NaOH, Na2CO3NaOH,{\text{ }}N{a_2}C{O_3} and inert impurities weighing. You are asked to find out the % composition of the mixture. You are also given a reagent that can react with the sample, say, HCLHCL along with its concentration (M1{M_1}).
We first dissolve the mixture in water to make a solution and then we add two indicators in it, namely phenolphthalein and methyl orange. Now, we titrate this solution with HCLHCL .
NaOHNaOH is a strong base while Na2CO3N{a_2}C{O_3} is a weak base. So it is safe to assume that NaOHNaOH reacts with HCLHCL first, completely and only then does Na2CO3N{a_2}C{O_3} react.

Note: A titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution.Typically,the titrant(the known solution) is added from a burette to a known quantity of analyte (the unknown solution) until the reaction is complete.