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Question: A mixture of \({C_3}{H_8}(g)\& {O_2}\)having total volume \(100ml\) in an Eudiometer tube is sparked...

A mixture of C3H8(g)&O2{C_3}{H_8}(g)\& {O_2}having total volume 100ml100ml in an Eudiometer tube is sparked & it is observed that a contraction of 45ml45ml is observed what can be the composition of reacting mixture.
A) 15  ml  C3H8  &  85ml  O215\;ml\;{C_3}{H_8}\;\& \;85ml\;{O_2}
B) 25  ml  C3H8  &  75ml  O225\;ml\;{C_3}{H_8}\;\& \;75ml\;{O_2}
C) 45  ml  C3H8  &  55ml  O245\;ml\;{C_3}{H_8}\;\& \;55ml\;{O_2}
D) 55  ml  C3H8  &  45ml  O255\;ml\;{C_3}{H_8}\;\& \;45ml\;{O_2}

Explanation

Solution

We know that propane reacts with oxygen to produce carbon dioxide and water molecules. And we also know that moles of a substance is equivalent to the volume of that substance at standard conditions of temperature and pressure.

Complete solution:
As we know that one mole of propane reacts with five moles of oxygen and results in the formation of three carbon dioxide and four water molecules. We also know that the number of moles is equivalent to the ratio of volume of the gas to 22.4L22.4L.
Thus, we can also say that 1ml1ml of propane reacts with 5ml5ml of oxygen to give 3ml3ml of carbon dioxide and 4ml4ml of water.
So, let us assume that propane acts as a limiting reagent which means that it will be completely consumed. So, when 15ml15ml of propane reacts with 75ml75ml of oxygen gas, 45ml45ml of carbon dioxide will be obtained.
And we are given that the contraction is observed as 45ml45ml. Hence, the contraction in the volume will be equivalent to the sum of all the volumes so it is given as: 15+7545=45ml15 + 75 - 45 = 45ml.
Similarly, if we assume oxygen as the limiting reagent. So when 25ml25ml propane reacts with 75ml75ml of carbon dioxide will be formed, then the contraction will be given as: 5+2575=45ml5 + 25 - 75 = 45ml.
Therefore, we can assume that this contraction is possible when the reaction mixture can be either 15  ml  C3H8  &  85ml  O215\;ml\;{C_3}{H_8}\;\& \;85ml\;{O_2} or 25  ml  C3H8  &  75ml  O225\;ml\;{C_3}{H_8}\;\& \;75ml\;{O_2}.

Hence, from the above explanation we can say that the correct answers are (A) and (B).

Note: Always remember that the limiting reagent is that reactant which will be completely consumed first during the course of a reaction. Also remember that the contraction in the volume is basically the term which is defined as the decrease in the volume of that particular substance.