Question
Question: A mixture of \({{C}_{3}}{{H}_{8}}\) and \(C{{H}_{4}}\) exerts a pressure of 320 mm of Hg at temperat...
A mixture of C3H8 and CH4 exerts a pressure of 320 mm of Hg at temperature T (K) in a V litre flask. On complete combustion, a gaseous mixture contains CO2 only, and exerts a pressure of 448 mm of Hg under identical condition. Hence, mole fraction of C3H8 in the mixture is:
(A) 0.2
(B) 0.8
(C) 0.25
(D) 0.75
Solution
There are five basic types of chemical reactions, which will be useful for predicting the products of unknown reactions. The types of chemical reactions are combination, decomposition, single-replacement, double-displacement reaction, and combustion reaction. This classification allows us to analyze the reactants and products of a given reaction. There is a way to express the relative amount of substances in a mixture with the mole fraction.
Complete step by step solution:
In the given combustion reaction,
Let V liter at temperature T (K), the pressure = 320 mm of Hg represents 1 mole
Then, V liter at temperature T (K), the pressure = 448 mm of Hg represents 320448mol = 1.4 mol
The complete combustion reactions of a given mixture of C3H8 and CH4are,
Let moles of C3H8 = x moles, then moles of CO2 = 3x moles
C3H8(g)+5O2→3CO2(g)+4H2O(l)
Moles of CH4 = 1-x moles,
CH4(g)+5O2→3CO2(g)+4H2O(l)
Moles of CO2 produced = 3x+1-x = 1+2x
Moles of CO2 produced = moles represents at V litre at temperature T (K) under pressure 448 mm of Hg
1+2x = 1.4
x=0.2
Therefore, mole fraction of C3H8 = 1x =0.2
Hence, mole fraction of C3H8 in the mixture = 0.2
The correct answer is option A.
Note: The ratio of moles one substance in a mixture to the total number of moles of all substances is called mole fraction. The mole fraction is helpful to calculate the mixture of gases. This mole fraction represents the number of molecules of a particular component in a mixture and expresses the concentration of the solution.