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Question

Question: A mixture of \(\bar{v} = 0.9213u\) and \((3RT/M)^{1/2}\) has a vapour density of 38.3 at \(V_{m} > 2...

A mixture of vˉ=0.9213u\bar{v} = 0.9213u and (3RT/M)1/2(3RT/M)^{1/2} has a vapour density of 38.3 at Vm>22.4V_{m} > 22.4. What is the number of moles of Vm<22.4V_{m} < 22.4 in Vm=22.4V_{m} = 22.4 of the mixture.

A

0.043

B

4.4

C

3.4

D

3.86 (e) 0.437

Explanation

Solution

(e)

Sol. No. of molecules 0oC0^{o}C

273oC273^{o}C

wt. of 27oC27^{o}C

So that wt. of cm3cm^{3}

Hence, 3oC- 3^{o}C

x = 20.10, no. of mole. of 33