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Question: A mirror is inclined at an angle \[\theta \]with the horizontal. If a ray of light is incident on th...

A mirror is inclined at an angle θ\theta with the horizontal. If a ray of light is incident on the mirror at an angleθ\theta , then the reflected ray makes the following angle with the horizontal:
A) θ\theta
B) 2θ2\theta
C) θ2\dfrac{\theta }{2}
D) 90{90^ \circ }

Explanation

Solution

In this question, we need to determine the angle made by the reflected ray with the horizontal. Here we will use the concept of law of Reflection which states that “When light is reflected from a surface then the angle of incidence is always equal to the angle of reflection, incidence angle and the reflected angle is measured from the path of the light to the normal to the surface to point at which light strikes this is known as law of reflection”.

Complete step by step answer:
Let AB be the mirror inclined at an angle θ\theta with the plane AM
Now a ray of light PQ\overrightarrow {PQ} is incident at an angle θ\theta on the plane mirror AB, we know Snell’s law states that when a light is incident on a plane mirror at an angle θ\theta then the light will be reflected by making an angle θ\theta .
Hence we can say QR\overrightarrow {QR} the reflected ray will also make an angle θ\theta
Now draw a line XY normal to the mirror AB, therefore we can say
PQX=RQX\angle PQX = \angle RQX

Now extend back the reflected ray QR\overrightarrow {QR} to the surface AM at point S.
Since RQB=90θ\angle RQB = {90^ \circ } - \theta
AQS=90θ\therefore \angle AQS = {90^ \circ } - \theta [By law of reflection]
Now in AQS\vartriangle AQS
QAS=θ\angle QAS = \theta
AQS=90θ\angle AQS = {90^ \circ } - \theta
As we know the total internal angle of a triangle is equal to180{180^ \circ }, therefore in the AQS\vartriangle AQS

QAS+AQS+QSA=180 θ+90θ+QSA=180 QSA=90  \angle QAS + \angle AQS + \angle QSA = {180^ \circ } \\\ \Rightarrow \theta + {90^ \circ } - \theta + \angle QSA = {180^ \circ } \\\ \Rightarrow \angle QSA = {90^ \circ } \\\

Hence the reflected ray makes an angle 90{90^ \circ } with the horizontal AM
Option D is correct.

Note: Students must be careful while using the angle of incidence and the reflection as we have to always take only similar angles that are either made with the horizontal or the vertical.