Question

A milliammeter of range 10 mA has a coil of resistance $1\Omega$. To use it as a voltmeter of range 10 V, the resistance that must be connected in series with it is

• A. $999\,\Omega$
• B. $1000\,\Omega$
• C. $9\,\Omega$
• D. $99\,\Omega$

Answer 1

Answer: (A)

$999\,\Omega$

Answer 2

R $\frac{V}{I_g}$ -G = $\frac{10}{10 \times 10^{-3}}$ - 1 = 1000 - 1 = 9999 $\Omega$