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Question: A microwave telephone link operating at the central frequency of 10 GHz has been established if 2% o...

A microwave telephone link operating at the central frequency of 10 GHz has been established if 2% of this is available for microwave communication channel, then how many telephone channels can be simultaneously granted if each telephone is allotted a bandwidth of 8 kHz?

A

1.5 x 103

B

3.5 x 102

C

2.5 x 104

D

4.5 x 106

Answer

2.5 x 104

Explanation

Solution

: Microwave frequency used in telephone link

=10GHz=10×109Hz=1010Hz= 10GHz = 10 \times 10^{9}Hz = 10^{10}Hz

Frequency available for microwave communication

=2%of10GHz=2100×1010=2×108Hz= 2\% of10GHz = \frac{2}{100} \times 10^{10} = 2 \times 10^{8}Hz

Bandwidth of each telephone channel

=8KHz=8×103Hz= 8KHz = 8 \times 10^{3}Hz

Number of microwave telephone channels

=2×1088×103=2.5×104= \frac{2 \times 10^{8}}{8 \times 10^{3}} = 2.5 \times 10^{4}