Solveeit Logo

Question

Physics Question on Current electricity

A microammeter has a resistance of 100Ω100 \Omega and full scale range of 50μA50 \mu A. It can be used as a voltmeter or as a higher range ammeter provided a resistance is added to it. Pick the correct range and resistance combination (s)

A

50 V range with 10kΩ10 k \Omega resistance in series

B

10 V range with 2000kΩ2000 k \Omega resistance in series

C

5 mA range with 1Ω1 \Omega resistance in parallel

D

10 mA range with 1Ω1 \Omega resistance in parallel

Answer

5 mA range with 1Ω1 \Omega resistance in parallel

Explanation

Solution

To increase the range of ammeter a parallel resistance (cal led shunt) is required which is given by
S=(igiig)G\, \, \, \, \, \, \, \, \, \, \, \, S = \bigg( \frac{i_g}{i - i_g} \bigg)G
For option (c)
S=(50×10650×10350×106)(100)1Ω\, \, \, \, \, \, \, \, \, \, S = \bigg( \frac{ 50 \times 10^{-6}}{50 \times 10^{-3} - 50 \times 10^{-6}} \bigg) (100) \approx 1 \Omega
To change it in voltmeter, a high resistance R is put in series,
where R is given by r=VigG r = \frac{V}{i_g} - G
For option (b), R=1050×106100200kΩR = \frac{10}{50 \times 10^{-6}} - 100 \approx 200k \Omega
Therefore, options (b) and (c) are correct.