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Question: A metre stick is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put on...

A metre stick is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12 cm mark, the stick is found to be balanced at 45 cm. The mass of the metre stick is

A

56 g

B

66 g

C

76 g

D

86 g

Answer

66 g

Explanation

Solution

Let m be the mas of the metre stick concentrated at C, the 50 cm mark as shown in the figure.

In equilibrium, taking moments of forces about C’ we get

10g (45-12) = mg (50-45)

10 g × 33 = mg × 5

m=10×335=66gm = \frac{10 \times 33}{5} = 66g