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Question

Physics Question on Thermal Expansion

A metre scale made of steel reads accurately at 25C25^{\circ} C . Suppose in an experiment an accuracy of 0.06mm0.06\, mm in 1m1\,m is required, the range of temperature in which the experiment can be performed with this metre scale is (coefficient of linear expansion of steel is 11×106/C 11 \times 10^{-6} /^{\circ} \, C )

A

19C19^{\circ} C to 31C31^{\circ} C

B

25C25^{\circ} C to 32C32^{\circ} C

C

18C18^{\circ} C to 25C25^{\circ} C

D

18C18^{\circ} C to 32C32^{\circ} C

Answer

19C19^{\circ} C to 31C31^{\circ} C

Explanation

Solution

The correct answer is A:19C  to  30C19\degree C\space to\space 30\degree C
Given, Coefficient of linear expansion of steel,
α=11×106/C\alpha=11 \times 10^{-6} /{ }^{\circ} C
We know that,
Δl=lαΔt\Delta l=l \alpha \Delta t
Δt=Δllα\Rightarrow \Delta t=\frac{\Delta l}{l \alpha}
Here, Δl=6×105ml=1m\Delta l=6 \times 10^{-5} m \Rightarrow l=1 m
Δt=6×1051×11×106\Delta t=\frac{6 \times 10^{-5}}{1 \times 11 \times 10^{-6}}
=5.45C=5.45^{\circ} C
So, the range of temperature in which the experiment can be hence performed him this metre scale will be 19C19^{\circ} C to 31C31^{\circ} C