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Question: A metallic spherical shell has an inner radius \(R_{1}\)and outer radius \(R_{2}.\) A charge is plac...

A metallic spherical shell has an inner radius R1R_{1}and outer radius R2.R_{2}. A charge is placed at the centre of the spherical cavity. The surface charge density on the inner surface is.

A

q4πR12\frac{q}{4\pi R_{1}^{2}}

B

q4πR12\frac{- q}{4\pi R_{1}^{2}}

C

q24πR22\frac{q^{2}}{4\pi R_{2}^{2}}

D

2q4πR22\frac{2q}{4\pi R_{2}^{2}}

Answer

q4πR12\frac{- q}{4\pi R_{1}^{2}}

Explanation

Solution

: When a charge + q is placed at the centre of spherical cavity as shown in Figur

Charge induced on the inner surface of shell

= + q …(i)

Charge induced on the outer surface of shell

= + q …(ii)

\thereforeSurface charge density on the inner surface=q4πR12= \frac{- q}{4\pi R_{1}^{2}}