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Question

Physics Question on Electric Charge

A metallic spherical shell has an inner radius R1R_1 and outer radius R2R_2. A charge is placed at the centre of the spherical cavity, the surface charge density on the outer surface is

A

q4πR12\frac{-q}{4\pi R^{2}_{1}}

B

q4πR22\frac{q}{4\pi R^{2}_{2}}

C

q24πR12\frac{q^2}{4\pi R^{2}_{1}}

D

2q4πR22\frac{2q}{4\pi R^{2}_{2}}

Answer

q4πR22\frac{q}{4\pi R^{2}_{2}}

Explanation

Solution

Surface charge density on the outer surface =+q4πR22=\frac{+q}{4\pi R^{2}_{2}} When a charge +q+q is placed at the centre of spherical cavity as shown in figure.