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Question: A metallic sphere of mass M falls through gllycerine with a terminal velocity v. if we drop a ball o...

A metallic sphere of mass M falls through gllycerine with a terminal velocity v. if we drop a ball of mass 8M of same metal into a column of glycerine. The terminal velocity of the ball will be.

A

2 v

B

4 v

C

8 v

D

16 v

Answer

4 v

Explanation

Solution

M=43πr3ρM = \frac{4}{3}\pi r^{3}\rho and 8M=43πR3ρ8M = \frac{4}{3}\pi R^{3}\rho

R3=8r3\therefore R^{3} = 8r^{3} or R = 2r

As vr2v \propto r^{2}

vv=(Rr)2=(2rr)2=4orv=4v\therefore\frac{v'}{v} = \left( \frac{R}{r} \right)^{2} = \left( \frac{2r}{r} \right)^{2} = 4orv' = 4v