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Question

Physics Question on Electromagnetic induction

A metallic rod of length ' LL ' is rotated with an angular speed of ' ω\omega ' normal to a uniform magnetic field ' BB ' about an axis passing through one end of rod as shown in figure The induced emf will be :
Rod in circular motion

A

12B2L2ω\frac{1}{2} B ^2 L ^2 \omega

B

14BL2ω \frac{1}{4} BL ^2 \omega

C

12BL2ω\frac{1}{2} BL ^2 \omega

D

14B2Lω \frac{1}{4} B ^2 L \omega

Answer

12BL2ω\frac{1}{2} BL ^2 \omega

Explanation

Solution

The correct answer is (C) : 12BL2ω\frac{1}{2} BL ^2 \omega
Rod in moment

∫dε=∫B(ωx)dx
ε=Bω0∫L​xdx=2BωL2​