Solveeit Logo

Question

Physics Question on Magnetic Field

A metallic rod of length 2020 cm is placed in North-South direction and is moved at a constant speed of 20 m/s towards East. The horizontal component of the Earth’s magnetic field at that place is 4×1034 × 10^{–3} T and the angle of dip is 45º45º. The emf induced in the rod is __________mV.

Answer

The emf induced in the rod is 16\underline{16} mV.

E=BlvE = Blv

=4×103×20100×204×10^{−3}×\frac{20}{100}×20 VoltsVolts

= 16  mV16\; mV