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Question

Physics Question on Electromagnetic induction

A metallic rod of 1m1 \,m length is rotated with a frequency of 5050 revolution per second, with one end hinged at the centre and the other end at the circumference of a circular metallic ring of radius 1m1\, m about an axis passing through the centre and perpendicular to the plane of the ring. AA constant uniform magnetic field of 1T1 \,T parallel to the axis is present everywhere. The emf between the centre and the metallic ring is

A

157V157\,V

B

117V117\,V

C

127V127\,V

D

137V137\,V

Answer

157V157\,V

Explanation

Solution

Formula for EE is E=12Bωl2E =\frac{1}{2} B \omega l ^{2} =12×2π×50×1×1×2=\frac{1}{2} \times 2 \pi \times 50 \times 1 \times 1 \times 2 =50π=50 \pi =157V=157 \,V