Question
Physics Question on Youngs double slit experiment
A metallic bar of Young’s modulus, 0.5 × 1011 N m–2 and coefficient of linear thermal expansion 10–5 °C–1, length 1 m and area of cross-section 10–3 m2 is heated from 0°C to 100°C without expansion or bending. The compressive force developed in it is :
A
5 × 103 N
B
50 × 103 N
C
100 × 103 N
D
2 × 103 N
Answer
50 × 103 N
Explanation
Solution
Thermal stress is:
Stress=Y⋅α⋅ΔT.
The force is:
F=Stress⋅A=Y⋅α⋅ΔT⋅A.
Substituting values:
F=0.5×1011⋅10−5⋅100⋅10−3=50×103N.