Question

A metal X crystallizes in a face – centred cubic arrangement with the edge length 862 pm. What is the shortest separation of any two nuclei of the atoms?

• A. 406 pm
• B. 707 pm
• C. 862 pm
• D. $609.6pm$

Answer 1

Answer: (D)

$609.6pm$

Answer 2

For fcc arrangement, distance of nearest neighbour is

$d = \frac{a}{\sqrt{2}} = \frac{862}{1.414} = 609.6$