Question
Question: A metal wire of linear mass density of 9.8g/m is stretched with a tension of 1kg-wt between two rigi...
A metal wire of linear mass density of 9.8g/m is stretched with a tension of 1kg-wt between two rigid supports 1m apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is :
(A) 50Hz
(B) 100Hz
(C) 200Hz
(D) 25Hz
Solution
When a condition of resonance is satisfied the frequency of the string matches with the frequency of the source of the vibration. For this question we will apply the formula of the frequency of a string between two fixed supports.
Complete step by step answer:
The frequency of the string attached between supports is given by: f=2l1μT, where lis the distance between the two rigid supports. Tis the tension of the string and μis the linear mass density.
Putting the values given in the question of the above-mentioned parameters, the frequency of the vibrating string: