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Question

Physics Question on Waves

A metal wire of linear mass density of 9.8gm19.8 \, g \, m^{- 1} is stretched with a tension of 10kgwt10 \, kg-wt between two rigid supports 1m1 \, m apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency nn . The frequency nn of the alternating sources is

A

50Hz50Hz

B

100Hz100Hz

C

200Hz200Hz

D

25Hz25Hz

Answer

50Hz50Hz

Explanation

Solution

The wire will vibrate with the same frequency as that of the source. This can be considered as an example of forced vibration. T=10×9.8N=98NT=10\times 9.8N=98N m=9.8×103kgm1m=9.8\times 10^{- 3}kgm^{- 1} Frequency of wire n=12L(Tm)n=\frac{1}{2 L}\sqrt{\left(\frac{T}{m}\right)} =12×1(989.8×(10)3)=50Hz=\frac{1}{2 \times 1}\sqrt{\left(\frac{98}{9.8 \times \left(10\right)^{- 3}}\right)}=50Hz