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Question: A metal sphere of radius r and specific heat S is rotated about an axis passing through its centre a...

A metal sphere of radius r and specific heat S is rotated about an axis passing through its centre at a speed of n rotations per second. It is suddenly stopped and 50 % of its energy is used in increasing its temperature. Then the rise in temperature of the sphere is –

A

2π2n2r25S\frac{2\pi^{2}n^{2}r^{2}}{5S}

B

π2n210r2S\frac{\pi^{2}n^{2}}{10r^{2}S}

C

78\frac{7}{8}pr2n2S

D

5(πrn)214S\frac{5(\pi rn)^{2}}{14S}

Answer

2π2n2r25S\frac{2\pi^{2}n^{2}r^{2}}{5S}

Explanation

Solution

I = 25\frac{2}{5} mr2, w = 2pn.

k = 12\frac{1}{2} Iw2 = 12\frac{1}{2} × 25\frac{2}{5} mr2 × 4p2 n2

= 43\frac{4}{3} p2 mr2n2

Dq = ΔQmS\frac{\Delta Q}{mS} = k/2mS\frac{k/2}{mS} = 25\frac{2}{5} π2mr2n2mS\frac{\pi^{2}mr^{2}n^{2}}{mS} = 2π2r2n25S\frac{2\pi^{2}r^{2}n^{2}}{5S}