Question

A metal rod of silver at 0°C is heated to 100°C. It's length is increased by 0.19 cm. Coefficient of cubical expansion of the silver rod is

• A. 5.7 × 10^–5/°C
• B. 0.63 × 10^–5/°C
• C. 1.9 × 10^–5/°C
• D. 16.1 × 10^–5/°C

Answer 1

Answer: (A)

5.7 × 10^–5/°C

Answer 2

$\alpha = \frac{\Delta L}{L_{0}(\Delta\theta)} = \frac{0.19}{100(100 - 0)} = 1.9 \times 10^{- 5}/{^\circ}C$

Now γ = 3α = 3 × 1.9 × 10^–5/°C = 5.7 × 10^–5/°C