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Question: A metal rod of length 2 m is rotating with an angular velocity of 100 rad/sec in a plane perpendicul...

A metal rod of length 2 m is rotating with an angular velocity of 100 rad/sec in a plane perpendicular to a uniform magnetic field of 0.3 T. The potential difference between the ends of the rod is

A

30 V

B

40 V

C

60 V

D

600 V

Answer

60 V

Explanation

Solution

e=12Bl2ω=12×0.3×(2)2×100=60Ve = \frac{1}{2}Bl^{2}\omega = \frac{1}{2} \times 0.3 \times (2)^{2} \times 100 = 60V