Question

A metal $M$ on heating in nitrogen gas gives $Y. Y$ on treatment with $H_2O$ gives a colourless gas which when passed through $CuSO_4$ solution gives a blue colour. $Y$ is

• A. $NH_3$
• B. $Mg(NO_3)_2$
• C. $Mg_3N_2$
• D. $MgO$

Answer 1

Answer: (C)

$Mg_3N_2$

Answer 2

$3\underset{\text{M}}{ {M}}$ ${g+N2->M}$ $\underset{\text{Y}}{ {g_3}}$ ${N2}$ $M\underset{\text{Y}}{ {g3}}$ ${N2 + 6H2O ->3Mg(OH)2 + }$ $\underset{\text{colourless}}{ {2NH3 ?}}$ ${}$ $M\underset{\text{}}{ {}}$ ${CuSO4 + 4NH3 -> }$ $\underset{\text{Blue complex}}{ {[Cu(NH3)4]SO4}}$ ${}$