Question

A metal M of equivalent mass E forms an oxide of molecular formula $M_x O_y$. The atomic mass of the metal is given by the correct equation

• A. $2E \left( \frac{y}{x} \right)$
• B. xyE
• C. E / y
• D. y / E

Answer 1

Answer: (A)

$2E \left( \frac{y}{x} \right)$

Answer 2

Let the atomic mass of metal, 'M' = a
Given, equivalent mass of metal, M = E
$xM + y O \rightarrow M_x O_y$
$\therefore$ 'xa' g metal 'M' reacts with oxygen = 16y g,
According to law of chemical equivalents $w \propto E$
$\frac{w_1}{w_2} = \frac{E_1}{E_2}$
$\frac{xa}{16y} =\frac{E}{8}$
$a = 2E \left( \frac{y}{x} \right)$