Question

A metal ion from the first transition series has a magnetic moment (calculated) of 3.87 B.M. How many unpaired electrons are expected to be present in the ion?

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (C)

3

Answer 2

3.87 = $\sqrt{n(n + 2)}$; n = number of unpaired electrons. So n = 3.