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Question

Physics Question on Electromagnetic induction

A metal disc of radius 100cm100 \,cm is rotated at a constant angular speed of 6060 rad/s in a plane at right angles to an external field of magnetic induction 0.05Wb/m20.05\, Wb/m^2. The emf induced between the centre and a point on the rim will be

A

3 V

B

1.5 V

C

6 V

D

9 V

Answer

1.5 V

Explanation

Solution

Induced emf produced between the centre and a point on the disc is given by e=12ωBR2e = \frac{1}{2}\omega BR^{2} Putting the values, ω=60rad/s,B=0.05Wb/m2\omega = 60rad/s,\, B=0.05\, Wb/m^{2} and R=100cm=1mR = 100\, cm = 1m We get e=12×60×0.05×(1)2=1.5Ve = \frac{1}{2} \times60\times 0.05\times \left(1\right)^{2} = 1.5V