Question

A metal crystallizes in a body centered cubic lattice (bcc) with the edge of the unit cell 5.2Å. The distance between the two nearest neighbour is

• A. 10.4 Å
• B. 4.5 Å
• C. 5.2Å
• D. 9.0Å

Answer 1

Answer: (B)

4.5 Å

Answer 2

Distance between two nearest neighbours in bcc = $\frac{\sqrt{3}a}{2}$

=$\frac{\sqrt{3} \times \sqrt{2}}{2}$ = $\frac{1.732 \times \sqrt{2}}{2}$ = 4.503 Å.