Question

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is $0.2 \times 10^{- 4}T$, then the e.m.f. developed between the two ends of the conductor is

• A. $5mV$
• B. $50\mu V$
• C. $5\mu V$
• D. $50mV$

Answer 1

Answer: (B)

$50\mu V$

Answer 2

Induced emf $e = \frac{1}{2}B_{H}l^{2}\omega$

$= \frac{1}{2} \times 0.2 \times 10^{- 4} \times (1)^{2} \times 5 = 5 \times 10^{- 5}V = 50\mu V$