Question

A metal conductor of length 1 m rotates vertically about one of its ends with an angular velocity 5 rad s-1. If the horizontal component of earth’s magnetic field is 0.2 x 10-4 T, then the emf developed between the ends of the conductor is

• A. 5$\mu$ V
• B. 5 mV
• C. 50 $\mu$V
• D. 50 mV

Answer 1

Answer: (C)

50 $\mu$V

Answer 2

The emf developed between the ends of the conductor is

$\varepsilon = \frac{1}{2}\omega Bl^{2} = \frac{1}{2} \times 5 \times 0.2 \times 10^{- 4} \times (1)^{2}$

$= 5 \times 10^{- 5}V = 50 \times 10^{- 6}V = 50\mu V$