Solveeit Logo

Question

Physics Question on electrostatic potential and capacitance

A medium having dielectric constant K>1K>1 fills the space between the plates of a parallel plate capacitor The plates have large area, and the distance between them is dd The capacitor is connected to a battery of voltage VV as shown in Figure (a) Now, both the plates are moved by a distance of d2\frac{d}{2} from their original positions, as shown in Figure (b)
medium having dielectric constant
In the process of going from the configuration depicted in Figure (a) to that in Figure (b), which of the following statement(s) is(are) correct?

A

The electric field inside the dielectric material is reduced by a factor of 2K2 K.

B

The capacitance is decreased by a factor of 1K+1\frac{1}{K+1}.

C

The voltage between the capacitor plates is increased by a factor of (K+1)(K+1).

D

The work done in the process DOES NOT depend on the presence of the dielectric material.

Answer

The capacitance is decreased by a factor of 1K+1\frac{1}{K+1}.

Explanation

Solution

For figure (a)
A medium having dielectric constant
E0=VdE_0 = \frac{V}{d}
C=Kε0AdC=\frac{Κε_0 Α}{d}

For figure (b)

A medium having dielectric constant
C=ε0A2dd+dkC`=\frac{ε_0A}{2d-d+\frac{d}{k}}

C=Kε0A(K+1)dC`=\frac{Κε_0 Α}{(K+1)d}

⇒$$C`=\frac{C}{K+1}