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Question: A \(2 \mu F\)capacitor is charged to 100volt and then its plates are connected by a conducting wire....

A 2μF2 \mu Fcapacitor is charged to 100volt and then its plates are connected by a conducting wire. The heat produced is

A

1J1 J

B

0.1J0.1 J

C

0.01 J

D

Answer

0.01 J

Explanation

Solution

Heat produced = Energy of charged capacitor

=12CV2= \frac { 1 } { 2 } C V ^ { 2 }

=12×(2×10−6)×(100)2=0.01 J= \frac { 1 } { 2 } \times \left( 2 \times 10 ^ { - 6 } \right) \times ( 100 ) ^ { 2 } = 0.01 \mathrm {~J}