Physics Question on Electromagnetic induction

Question

A massless square loop, of wire of resistance $10\, \Omega$ , supporting a mass of $1 \, g$ , hangs vertically with one of its sides in a uniform magnetic field of $10^3 G$ , directed outwards in the shaded region A de voltage $V$ is applied to the loop For what value of $V$ , the magnetic force will exactly balance the weight of the supporting mass of $1 g$ ?(If sides of the loop $=10 \, cm , g =10\, ms ^{-2}$ )
A massless square loop, of wire of resistance 10 Ω, supporting a mass of 1 g, hangs vertically with one of its sides in a uniform magnetic field

Answer 1

Solution

Fm=mg
∴ ILB =mg
∴(RV)LB=mg
∴V=LBmgR
=(0.1m)(103×10−4T)(1×10−3kg)(10m/s2)(10Ω)=10V