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Question

Physics Question on laws of motion

A mass of 6kg6 \,kg is suspended by a rope of length 2m2\, m from a ceiling. A force of 50N50 \,N in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is

A

5050{}^\circ

B

6060{}^\circ

C

3030{}^\circ

D

4040{}^\circ

Answer

4040{}^\circ

Explanation

Solution

tanθ=506g=0.83\tan \theta =\frac{50}{6g}=0.83 or tan θ=tan 40tan\text{ }\theta =tan\text{ }40{}^\circ or θ=40\theta =40{}^\circ