Solveeit Logo
Login

Question

Physics Question on Newton’s Second Law Of Motion

A mass of 200 gm has initial velocity vi=2i^+3j^v_i = 2\hat{i}+3\hat{j} and final velocity vf=−2i^−3j^v_f=-2\hat{i}-3\hat{j} find magnitude of change in momentum

A

∣Δp⃗∣=0.8i^−1.2j^|\Delta\vec{p}|=0.8\hat{i}-1.2\hat{j}

B

∣Δp⃗∣=3.04|\Delta\vec{p}|=3.04

C

∣Δp⃗∣=2.04|\Delta\vec{p}|=2.04

D

∣Δp⃗∣=1.44|\Delta\vec{p}|=1.44

Answer

∣Δp⃗∣=1.44|\Delta\vec{p}|=1.44

Explanation

Solution

The correct option is (D): ∣Δp⃗∣=1.44|\Delta\vec{p}|=1.44.