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Question

Physics Question on Oscillations

A mass of 2.0kg2.0\, kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion . The spring constant is 200N/m200\, N/m . What should be the minimum amplitude of the motion so that the mass gets detached from the pan (take g=10m/s2g = 10 \,m /s^2 ).

A

10 . 0 cm

B

any value less than 12.0 cm

C

4. 0 cm

D

8.0 cm

Answer

10 . 0 cm

Explanation

Solution

For given conditions mg=mω2akam g=m \omega^{2} \,a-k a
a=mgk=2×10200=0.1=10cm\Rightarrow a =\frac{ mg }{ k }=\frac{2 \times 10}{200}=0.1=10 \,cm