Solveeit Logo
Login

Question

Question: A mass of 10 gm moving with a velocity of 100 cm/s strikes a pendulum bob of mass 10 gm. The two mas...

A mass of 10 gm moving with a velocity of 100 cm/s strikes a pendulum bob of mass 10 gm. The two masses stick together. The maximum height reached by the system now is (g=10m/s2)(g = 10m/s^{2})

A

Zero

B

5 cm

C

2.5 cm

D

1.25 cm

Answer

1.25 cm

Explanation

Solution

Initially mass 10 gm moves with velocity 100 cm/s

∴ Initial momentum = 10 × 100 =

After collision system moves with velocity then

Final momentum =

By applying the conservation of momentum

10000 = ⇒

If system rises upto height h then

h=vsys. 22g=50×502×1000=2.52=1.25 cmh = \frac { v _ { \text {sys. } } ^ { 2 } } { 2 g } = \frac { 50 \times 50 } { 2 \times 1000 } = \frac { 2.5 } { 2 } = 1.25 \mathrm {~cm}