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Question

Physics Question on Conservation of energy

A mass of 1 kg is thrown up with a velocity of 100 m/s. After 5 seconds, it explodes into two parts. One part of mass 400 g comes down with a velocity 25 m/s, Calculate the velocity of other part:

A

40 m/s upward40\ m/s \ upward

B

40 m/s downward40 \ m/s\ downward

C

100 m/s upward100\ m/s \ upward

D

60 m/s upward60\ m/s\ upward

Answer

100 m/s upward100\ m/s \ upward

Explanation

Solution

Velocity after 5 secondVelocity\ after \ 5 \ second

v=10010×5v=100–10×5

v=50 m/s.v = 50 \ m/s.

from conservation of momentumfrom\ conservation \ of \ momentum

1×50j^=0.4×25(j^)+0.6v1×50\hat j=0.4×25(-\hat j)+0.6\vec v

50j^+10j^=0.6v50\hat j+10\hat j=0.6\vec v

v=60j^0.6=100j^=100 m/s j^\vec v=\frac {60\hat j }{0.6} =100\hat j=100\ m/s\ \hat j

So, the correct option is (C):So, \ the\ correct\ option\ is \ (C): 100 m/s upward100\ m/s \ upward