Solveeit Logo

Question

Question: A mass of 0.5kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearl...

A mass of 0.5kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearly weightless spring of force constant k=50 N/mk = 50 \mathrm {~N} / \mathrm { m }. The maximum compression of the spring would be

A

0.15 m

B

0.12 m

C

1.5 m

D

0.5 m

Answer

0.15 m

Explanation

Solution

The kinetic energy of mass is converted into potential energy of a spring

12mv2=12kx2\frac { 1 } { 2 } m v ^ { 2 } = \frac { 1 } { 2 } k x ^ { 2 }x=mv2k=0.5×(1.5)250=0.15 mx = \sqrt { \frac { m v ^ { 2 } } { k } } = \sqrt { \frac { 0.5 \times ( 1.5 ) ^ { 2 } } { 50 } } = 0.15 \mathrm {~m}