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Question

Physics Question on Conservation of energy

A mass of 0.5kg0.5\, kg moving with a speed of 1.5m/s1.5\, m/ s on a horizontal smooth surface, collides with a nearly weightless spring of force constant k=50N/mk = 50\, N/m. The maximum compression of the spring would be

A

0.5m0.5\,m

B

0.15m0.15\,m

C

0.12m0.12\,m

D

1.5m1.5\,m

Answer

0.15m0.15\,m

Explanation

Solution

Apply law of conservation of energy, 12mv2=12kx2\frac{1}{2}mv^{2}=\frac{1}{2} kx^{2}
mv2=kx2\Rightarrow mv^{2}=kx^{2} or 0.5×(1.5)2=50×x20.5\times\left(1.5\right)^{2}=50\times x^{2}
x=0.15m\therefore x=0.15\,m