Solveeit Logo

Question

Question: A mass m is vertically suspended from a spring of negligible mass; the system oscillates with a freq...

A mass m is vertically suspended from a spring of negligible mass; the system oscillates with a frequency n. What will be the frequency of the system if a mass 4 m is suspended from the same spring

A

n/4n / 4

B

4n4 n

C

n/2n / 2

D

2n2 n

Answer

n/2n / 2

Explanation

Solution

n=12πkmn1mn1n2=m2m1n = \frac { 1 } { 2 \pi } \sqrt { \frac { k } { m } } \Rightarrow n \propto \frac { 1 } { \sqrt { m } } \Rightarrow \frac { n _ { 1 } } { n _ { 2 } } = \sqrt { \frac { m _ { 2 } } { m _ { 1 } } }

nn2=4mmn2=n2\Rightarrow \frac { n } { n _ { 2 } } = \sqrt { \frac { 4 m } { m } } \Rightarrow n _ { 2 } = \frac { n } { 2 }