Question
Question: A mass M is suspended by two springs of force constants K<sub>1</sub> and K<sub>2</sub> respectivel...
A mass M is suspended by two springs of force constants K1 and K2 respectively as shown in the diagram. The total elongation (stretch) of the two springs is

A
K1+K2Mg
B
K1K2Mg(K1+K2)
C
K1+K2MgK1K2
D
K1K2MgK1+K2
Answer
K1K2Mg(K1+K2)
Explanation
Solution
For series combination
keq=k1+k2k1k2
⇒x=k1k2mg(k1+k2)