Question

A mass M is hung with a light inextensible string. Tension in horizontal part of string is

• A. $\sqrt { 3 }$ Mg
• B. $\sqrt { 2 }$ Mg
• C. Mg/ $\sqrt { 3 }$
• D. Mg/2

Answer 1

Answer: (A)

$\sqrt { 3 }$ Mg

Answer 2

Here T₁ = T₂ cos 30 = T₂ $\frac { \sqrt { 3 } } { 2 }$

i.e., T₂ = $\frac { 2 } { \sqrt { 3 } }$ T₁

Also Mg = T₂ sin 30^o = $\frac { \mathrm { T } _ { 2 } } { 2 }$

i.e., Mg = $\frac { 2 } { \sqrt { 3 } } \frac { \mathrm { T } _ { 1 } } { 2 } = \frac { \mathrm { T } _ { 1 } } { \sqrt { 3 } }$

i.e., T₁ = $\sqrt { 3 }$ Mg