Question
Question: A mass \[m\] falls on spring constant \[k\] and negligible mass from a height \[h\]. Assuming it sti...
A mass m falls on spring constant k and negligible mass from a height h. Assuming it sticks to the pan and executes simple harmonic motion, the maximum height upto which the pan will rise is:
A. kmg
B. kmg[1+mg2kh−1]
C. kmg[1+mg2kh+1]
D. kmg[1+mgkh−1]
Solution
For this question we will use the formula for potential energy. Potential energy is stored in the spring and after coming in motion potential energy decreases. Making a labeled diagram will help to solve the problem in a systematic way. Concept of simple harmonic motion has also been used. Sign convection should be taken care.
Formula used:
Potential energy E=mgh
Complete answer:
Let us consider a mass mfalling in a spring having spring constantk. The massm is falling from a height h. When the mass falls on the spring, the spring compresses and length changes. Let us assume x be the length of the spring after compression, so the total distance from which the spring is falling will be (h+x).
As we know potential energy is stored in the spring and when the system undergoes simple harmonic motion there will be loss of potential energy. This can be given as
mg(h+x)=21kx2
x2−(k2mg)x−k2mgh=0
Rearranging the terms,