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Question

Question: A mass is supported on a frictionless horizontal surface. It is attached to a string and rotates abo...

A mass is supported on a frictionless horizontal surface. It is attached to a string and rotates about a fixed centre at an angular velocity ω0. If the length of the string and angular velocity are doubled, the tension in the string which was initially T0 is now

A

T0

B

T0/2

C

4T0

D

8T0

Answer

8T0

Explanation

Solution

T=mω2lT = m\omega^{2}l

T2T1=(ω2ω1)2(l2l1)\frac{T_{2}}{T_{1}} = \left( \frac{\omega_{2}}{\omega_{1}} \right)^{2}\left( \frac{l_{2}}{l_{1}} \right)T2T0=(2ωω)2(2ll)\frac{T_{2}}{T_{0}} = \left( \frac{2\omega}{\omega} \right)^{2}\left( \frac{2l}{l} \right)T2=8T0T_{2} = 8T_{0}